In figure, if QA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then cd
is equal to
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1
Answer:
3cm
Step-by-step explanation:
OC is perpendicular on chord AB
∴OC bisects the chord AB
⇒AC=CB
Now,
AC+CB=AB
⇒AC+CB=8
⇒AC= 8/2
=4cm
=>ΔOCA is a right angled triangle
AO^2=AC^2+OC^2
5^2=4^2+OC^2
OC^2=5^2-4^2
OC^2=9
OC=√9
OC=3
Since, OD is the radius of the circle
OA=OD=5cm
CD=OD-DC
=5-2
=3cm
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