Question

In figure, if QA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then cd
is equal to
​

Answer 1

Answer:

3cm

Step-by-step explanation:

OC is perpendicular on chord AB

∴OC bisects the chord AB

⇒AC=CB

Now,

AC+CB=AB

⇒AC+CB=8

⇒AC= 8/2

=4cm

=>ΔOCA is a right angled triangle

AO^2=AC^2+OC^2

5^2=4^2+OC^2

OC^2=5^2-4^2

OC^2=9

OC=√9

OC=3

Since, OD is the radius of the circle

OA=OD=5cm

CD=OD-DC

=5-2

=3cm