In figure, if the semi perimeter of ABC triangle is 23cm then find AF + BD + CE.
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Alanaaron:
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Answer:
Step-by-step explanation:
(AB+BC+AC)/2=23cm
AF+BF+BD+DC+AE+CE=46cm.
AF+AE+BF+BD+CD+CE=46cm
Tangents drawn from external points to a circle are equal. Thus
2(AF+BD+CE)=46
AF+BD+CE=23cm
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You have taken semi perimeter as perimeter. Lol
Snowflake
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