In figure, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to
(a) 60°
(b) 70°
(c) 80°
(d) 90°
Answers
Answered by
7
Answer:
pls send the figure , so I will able to help you
#purple you armys
Answered by
94
Answer:
∠OPT = 90°
∠OQT = 90°
∠POQ = 110°
TPOQ is a quadrilateral
∠PTQ + ∠POQ = 180°
∠PTQ + 110° = 180°
∠PTQ = 180° – 110° = 70°
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