in figure ,if TP and TQ are two tangents to a circle with centere O so that angle POQ =110 degree ,then angle PTQ is equal to
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Answer:
PTQ=70
Step-by-step explanation:
we know that tangents are perpendicular to radius
thus, OPT=OQT=90
sum of all the angles of a quadrilateral is 360
therefore, OPT+OQT+POQ+PTQ=360
90+90+110+PTQ=360
290+PTQ=360
PTQ=360-290
PTQ=70
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