Question

in figure (ii) ABCD is a paralleogram with BAO = 30 Degree DAO =45 degree and COD = 30 degree .
DAO=45 degree COD = 30 degree.find ABO,ODC,ACB,CBD

Answer 1

AOB=105° ------vertically opposite angles
ABO=45°-------ANGLES SUM PROPERTY OF. TRIANGLES
ODC = 45° -------alternate interior angles
ACB= 45°---------alternate interior angles
CBD=60°

Answer 2

1. ABO

as diagonal of parallelogram bisects each other, AOB is a isosceles triangle.

the angles between the equal sides are equal so,

angle ABO = 30 degree.

2.ODC

again this is a isosceles triangle so,

angle ODC=45degree

3.ACB

triangle OBC is a isosceles triangle. also, linear pair the theorem angle BOC = 75degree.

rest 2 angles will be same

= 180 = 75+2x

= 180-75= 2x

= 105= 2x

=52.5 = angle ACB

4.CBD

angle A = 75degree

angle B = 180-75

= 105 degree