Physics, asked by 1207426, 11 hours ago

In Figure II, current of 0.10 A flows through a copper wire 0.10 x 10 -3 m in diameter and then through a salt solution contained in a glass tube 0.010 m in diameter. The density of conduction electrons in copper is 1.1 x 10 29 m -3 . The current in the solution is carried equally by positive and negative ions with charges 2e and the number of each ion species per unit volume is 6.1 x 10 23 m -3 . Figure II (i) Calculate the number of electrons passing through the wire EACH second

Answers

Answered by dkhkfuyf493
0

Answer:

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Explanatiogvrn:

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Answered by Himnishsoni
0

Answer:

In the figure, a 100 mA current flows through a copper wire 0.10 mm in diameter, a 1.0-cm-diameter glass tube containing a salt solution, and a vacuum tube where the current is carried by an electron beam 1.0 mm in diameter. The density of conduction electrons in copper is 1.1×1029 m−3 . The current in the solution is carried equally by positive and negative ions with charges ±2e;the density of each ion species is 6.1×1023 m−3 . The electron density in the beam is 2.2×1016 m−3 .(Figure 1)

Figure 1 of 1 1.0 cm 0.10 mm Wire Solution Vacuum tube 1.0 mm Wire Electron beam

Part A

Find the drift speed in the copper wire.

Express your answer using two significant figures.

Part B

Find the drift speed in the salt solution.

Express your answer using two significant figures.

Part C

Find the drift speed in the electron beam.

Express your answer using

Explanation:

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