Question

In figure ∆ is an equilateral triangle. Find the coordinates of point C.

Answer 1

Answer:

In the figure,

ABC and ABD are two equilateral triangles.

The length of side AB = 2a

Now,

Length of the side BC should be = AB = 2a

So,

Let us say the co-ordinate of the point C is (0, y).

So,

Length of side BC is given by,

Therefore, the co-ordinate of the point C will be,

C = (0, a√3)

Answer 2

Answer: C is at (0, √3a)

Explanation:

As ∆ABC is an equilateral triangle, then,

CO = altitude = (√3)/2 × s = (√3)/2 × AB

Now,

AB = a + a = 2a units.

So,

CO = (√3)/2 × 2a = (√3) a.

Therefore, the coordinates of C will be of (0, √3a) as x = 0 in Y - axis.