Question

in figure it is AB//CD,LAPQ =50 degree and <prd =127 degree .find x and y and z ​

Answer 1

Answer:

∠PQR=∠APQ  (Alternate angle)

x=50∘

∠PRQ+∠PRD=180∘

∠PRQ+127∘=180∘∠PRQ=180∘−127∘=53∘

∠PQR+∠QPR+∠PRQ=180∘ (Angle sum property of trianlge

x+y+53∘=180∘50∘+y+53∘=180∘y=180∘−103∘=77∘