Question

In figure, It is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.​

Answer 1

Answer:

In given triangles :

AB=CD

and,AD=BC

AC=AC because it is common

So,∆ADC congruent to ∆CBA

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given : AB = CD and AD = BC

to proved : ∆ADC ~= ∆CBA

proof: In ∆ADC and ∆CBA

AC=AC(Common side)

AB=CD (given)

AD= BC (given)

.°. ∆ADC ~=∆CBA ( by SSS congruence rule)

hence proved