Question

In figure , line AB Parallel line CD and line PQ is transversal. Ray PT and ray QT are bisectors of Angle BPQ and angle PQD respectively. Find measure of angle PTQ

Answer 1

the answer is 90°
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Answer 2

since ABllCD
SO,angle BPQ+angle PQD=180(allied angle )
since TP AND TQ r bisector of angle BPQ and PQD....
angle TPQ +angle TQP =90
SINCE
sum of all angle of ∆=180
angle TPQ+angle TQP+angle PTQ=180
=90+angle PTQ=180
=ANGLE PTQ=90 degree...



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