Question

In figure line PQ and RS intersect at O. If angle ROQ = 90 degree a:b=1:5 find the value of C​

Answer 1

${❥}\fbox\red{A}\fbox\orange{N}\fbox\purple{S}\fbox\green{W}\fbox\blue{E}\fbox\pink{R}$

Required answer-:

∠POR=3∠ROQ (Given)

∠POR+∠ROQ=180° (Linear pair)

⇒3∠ROQ+∠ROQ=180°

⇒4∠ROQ=180°

⇒∠ROQ=$\frac{180°}{4}$ =45°

Now ∠SOQ=∠POR

=3∠ROQ (Ver. opp. ∠s)

=3×45°=135°

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