Question

In figure, <ACB=40° then find <OAB.​

Answer 1

Answer:

140 degree is the answer

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Answer 2

Answer:

In triangle AOB,

Angle AOB= 40×2= 80°(angle made at the centre is twice the angle at the circumference)

AO= OB

Angle BAO= Angle OBA= X

X+x + 80= 180°

2x = 100°

X= 50°

Therefore Angle OAB= 50°

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