Question

In figure <B=<E, BD=CE and <1=<2,show that ∆Abc congruence to ∆AED

Answer 1

In ∆ABD and ∆ACE
<b=<c
BD=CE
<1=<2
∆Abd=~∆Ace(AAS) (1)
let <DAC be x
Add x on both side of eq 1)
∆Abd+x=∆Ace+x
∆Abc=~∆Ade