Question

In figure o is the center of the circle find x

Answer 1

In Δ APB
∠PBA = 40 degree
∠APB = 90 degree (semi-circle forms 90 degree angle)
thus, ∠APB +∠PBA +∠PAB = 180 (angle sum property)
∠PAB+40+90) =180
∠PAB = 180 - 130
∠PAB = ∠ x = 50 degree (angles on the same segment)
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