In figure, O is the centre of circle, angle CAO=30 and angle CBO=40 . find angle AOB.
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i am not very sure about my answer, but i believe
AOB = 140°
because in acb should be a sum of 40 and 30
i.e 70° (this is a rule)
the angle in the centre is always double of the angle on the circumference (provided both are suspended from same two points on the circumference)
so, 70×2 =140°
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