Question

in figure, O is the centre of the circle and A,B,C are the points on the circle. Find Angle AOC [ JOIN AO ].

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Answer 1

Answer:

1. 258988055543688131481535

Answer 2

Answer:

∠ADC=

2

1

∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=

2

1

×130=65

∘

Now, ADCB is cyclic quadrilateral ⇒

Sum of opposite Angles is 180

∘

∴∠ABC+∠ADC=180

∘

∠ABC+65=180

∘

∠ABC=115

∘

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