Question

in figure O is the centre of the circle Angle B equal to 60 degree and Angle c equal to 90 degree find angle OBC​

Answer 1

Answer:

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.

Therefore, ∠BOC=2n

∠OCB=m

Since, OB = OC = radius of the circle = m

Thus, in Δ OBC,

∠OCB+∠OBC+∠BOC=180

∘

2m+2n=180

⇒m+n=90