Math, asked by svakshkhanna, 6 months ago

In figure OA|| CD ||YZ, BAO=110° and BCD=130º. Find x.
i

А
130
110
B
N

Answers

Answered by suman5420
0

The value of x is 60^0600

Step-by-step explanation:

Given:

< OAB=110^0<OAB=1100

< BCD=130^0<BCD=1300

We need to find the < ABC<ABC

If a line is drawn parallel to OA and CD meeting the point B be XY line

Then since OA is parallel to XB we know that adjacent angles will make 180^01800

So we get as

\begin{gathered}110+ < XBA=180\\\\ < XBA=70^0\end{gathered}110+<XBA=180<XBA=700

Similarly with CD and BY we get as

\begin{gathered}130+ < CBY=180\\\\ < CBY=50^0\end{gathered}130+<CBY=180<CBY=500

The line makes an angle of 180^01800 at B so we get as

\begin{gathered} < XBA+ < CBY+ < ABC=180\\\\70+50+x=180\\\\x=60^0\end{gathered}<XBA+<CBY+<ABC=18070+50+x=180x=600

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