In figure OA|| CD ||YZ, BAO=110° and BCD=130º. Find x.
i
상
А
130
110
B
N
Answers
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0
The value of x is 60^0600
Step-by-step explanation:
Given:
< OAB=110^0<OAB=1100
< BCD=130^0<BCD=1300
We need to find the < ABC<ABC
If a line is drawn parallel to OA and CD meeting the point B be XY line
Then since OA is parallel to XB we know that adjacent angles will make 180^01800
So we get as
\begin{gathered}110+ < XBA=180\\\\ < XBA=70^0\end{gathered}110+<XBA=180<XBA=700
Similarly with CD and BY we get as
\begin{gathered}130+ < CBY=180\\\\ < CBY=50^0\end{gathered}130+<CBY=180<CBY=500
The line makes an angle of 180^01800 at B so we get as
\begin{gathered} < XBA+ < CBY+ < ABC=180\\\\70+50+x=180\\\\x=60^0\end{gathered}<XBA+<CBY+<ABC=18070+50+x=180x=600
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