in figure OA =OB,OC=OD and angle AOB=angle COD prove that AC=BD
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Answer:
AC=BD
Step-by-step explanation:
Given ∠AOB=∠COD
∠AOB−∠COB=∠COD−∠COB
∴∠AOC=∠DOB
In ΔAOC and ΔDOB
i)OA=OB(Given)
ii)OC=∠OD (Given)
iii)∠AOC=∠DOB (Proved above)
∴ΔAOC≅∠DOB
(SAS Axiom)
∴AC=BD
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