Question

In figure point P on a wheel of radius R is in contact with the ground.What is the displacement of the point when the wheel rolls a half revolution​

Answer 1

Answer:

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Answer 2

The displacement of point R will be R$\sqrt[]{4 + Pi^{2} }$

Displacement

• Displacement is the shortest length of the distance travelled between two points.

Step-by-step calculation

From the diagram, we can confer that,

Given:

Here, the horizontal displacement on half a revolution will be = pi x R

The vertical displacement of the point P is = 2R

Formula:

According to the formula for displacement

Displacement = $\sqrt{horizontal displacement^{2} + vertical displacement^{2} }$

Thus,

displacement of point p = $\sqrt{piR^{2} +( 2R)^{2} }$

Displacement = $\sqrt{piR^{2} + 4R^{2} }$

Result:

Displacement of point P =  R$\sqrt{pi^{2} + 4 }$

Therefore, The displacement of point R will be R$\sqrt[]{4 + Pi^{2} }$