Question

In figure, points G,D,E,F are concyclic points of a circle with center C. ECF = 70°, m(arc DGF)= 200°. Find m(arc DE) and m(arc DEF).
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Answer 1

Answer:

Answer

∠ECF=70°

=m(arcEF)=70°

m(arcDGF)=200°

m(arcDGF)+m(arcEF)+m(arcDE)=360°

200+70+m(arcDE)=360°

m(arcDE)=90°

m(arcDEF)=m(arcDE)+m(arcEF)

m(arcDEF)=90+70=160°

solution