Question

In figure, PQ and PR are two tangents to a circle with centre O. If angle QPR = 42°, then find angle QOR.​

Answer 1

Answer:

draw line op

Q=R=90

Angle QPO=RPO= 42/2= 21⁰ , that is 21 degree

angle PQO=PRO=90

By angle addition property

in triangles PQO and PRO

angle QOP+90+21=180

QOP=69⁰

similarly

angle ROP=69⁰

thus

angles , QOP+ROP=QOR

thus

Angle QOR=138⁰