In figure PQ is a chord of a circle with centre o and pt is a tangent .if angle QPT =60 find angle PRQ
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Answered by
569
Answer:
answer is 120
Step-by-step explanation:
given :PT is a tangent so ∠OPT=90
∠QPT =60
∠OPQ = ∠OPT-∠QPT
∠OPQ=90-60
∠OPQ=30
∠OPQ+∠OQP+POQ=180 (ANGLE SUM PROPERTY)
∠POQ=180-30-30
∠POQ=120
Angle OPQ= angle OQP = 30° ie.,
Angle POQ= 120°. Also, angle PRQ= ½ reflex angle POQ.
∠PRQ=1/2(360-120)
∠PRQ=240/2
∠PRQ=120
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