Math, asked by payalsingh009988776, 5 months ago

In figure, PQ is a diameter and PT is
a tangent of the circle with centre o.if angle QOS=150°, find angle PTS​

Answers

Answered by durgakyg
4

Answer:

∠QOT = 150°

∠POQ = 180° (LPA)

∠POT + 150° = 180°

∴∠POT = 30°

∠OPT = 90° (theorem...)

∴In ΔPOT,

∠POT + ∠OTP + ∠TPO = 180° (ASP of Δ)

30° +∠OTP + 90° = 180

∴∠OTP = 60°

Step-by-step explanation:

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