In figure, PQ is a tangent to the circle with
centre O, at the point B. If ∠AOB = 100°,
then find ∠ABP.
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Answer:
50° Given: AO and BC are the radius of the circle Since, AO = BO We know that the radius and tangent are perpendicular at their point of contact Read more on Sarthaks.com - https://www.sarthaks.com/159083/in-the-given-figure-the-centre-circle-chord-and-the-tangent-at-if-aob-100-then-bat-is-equal?show=159091#a159091
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