Question

In Figure, PQ is tangent to the circle with centre at O, at the point B. If angle AOB = 100°, then angle ABP in equal to
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Answer 1

Answer:

the answer is 50 compulsory

Answer 2

The angle ABP  = 50°

Step-by-step explanation:

Given that ∠ AOB = 100°

Since OA = OB

So  ∠ OAB =  ∠ OBA = 40°

Since PQ is tangent on the circle. So OB is perpendicular to PQ. So

∠ OBP = 90°

∠ OBA + ∠ ABP = 90°

∠ ABP  = 90 - ∠ OBA

⇒ ∠ ABP  = 90 - 40

⇒ ∠ ABP  = 50°

Thus the angle ABP  = 50°