Question

in figure PQ perpendicular to PS and PQ parallel to SR angle SQR=28° and angle QRT=65° . find the value of X and Y

Answer 1

find x by alternate angle property when 180-28-115
find y by 180 -x+90

Answer 2

Hello mate ☺

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Solution-

It is given that PQ∥SR. Therefore, ∠QRT=∠PQR              (Alternate Interior Angles)

⇒65°=x+28°

⇒x=65°−28°=37°

In ∆PQS, we have

x+y+∠SPQ=180°       (Sum of three angles of a triangle =180°)

⇒37°+y+90°=180°        ( It is given that ∠SPQ=90°)

⇒y=180°-37°−90°=53°

Therefore, x=37° and y=53°

I hope, this will help you.☺

Thank you______❤

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