In figure, PQ = PS. The value of x is
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Answer:
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Given:-
- In the given figure PQ = PS
- ∠Q = 110°
To Find:-
- The value of x [∠RPS]
Note:-
- Refer to the attachment for clear view of explanation.
Before solving:-
- Let us name the unknown angle with y
Solution:-
In the given figure,
There are two triangles,
1st ∆PQS which is an isosceles triangle who two sides and angles are equal.
2nd ∆PSR which is a scalene triangle.
Also in the figure,
∠PQY = 110°
So,
∠PQY + ∠PQS = 180° [Linear Pair]
= 110 + ∠PQS = 180°
=> ∠PQS = 180° - 110°
=> ∠PQS = 70°
Now,
In ∆PQS
PS = PQ
Therefore,
∠PSQ = ∠PSQ = 70°
Now,
In The figure again,
∠PSQ + ∠PSR = 180° [Linear Pair]
70° + ∠PSR = 180°
=> ∠PSR = 180° - 70°
=> ∠PSR = 110°
Therefore,
Now,
In ∆PSR,
∠PSR = 110°
∠SPR = x
∠PRS = 25°
According to angle - sum property of the triangle
∠PSR + ∠SPR + ∠PRS = 180°
= 110° + x + 25° = 180°
=> 135° + x = 180°
=> x = 180° - 135°
=> x = 45°
Therefore the value of x is 45° (option 2)
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Explore More!!
→ What is angle - sum property of a triangle?
✓ The angle - sum property of a triangle states that the sum of all angles of a triangle is always 180°
✭ The linear pair is always supplementary (180°)
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