Question

In figure, PQ RS, QPR = 70°, ROT = 20° find the value of x.

a. 20°

b. 70°

c. 50°

d. 110°​

Answer 1

Answer:

angle RS s is equals to 70 degrees

ROT is a triangle.

angle O = 20°

angle R = 180 - angle RS

180°-70° = 110°

sum of three angles of a triangle = 180 °

angle x = 180 -(sum of angle O and angle R)

180-(20+110)°

180°-130°

50°

therefore, X is 50°.

Answer 2

Given :

In Figure, PQ || RS, ∠QPR = 70° , ∠ROT = 20° . Find the value of x.

Solution :

Option c ⇒ 50°

Explanation :

Here, we know that PQ || RS and PO is the transversal.

∴ ∠R = ∠P (Corresponding angles)

⇒ ∠R = 70°

• We know exterior angle of a triangle is equal to the sum of the interior angles.

Applying exterior angle property in △TRO

⇒ ∠T + ∠O = ∠R

⇒ x + 20° = 70°

⇒ x = 70° - 20°

⇒ x = 50°