Question

In figure ∆pqr is such that pq=pr and angle qpr=50° find angle pst​

Answer 1

∠PST = 65°

Step-by-step explanation:

PQ = PR

∠PQR = ∠PRQ

∠QPR + ∠PQR + ∠PRQ = 180°

=> 50° + ∠PQR + ∠PRQ = 180°

=>∠PQR + ∠PRQ = 130°

∠PQR = ∠PRQ = 65°

QRTS is cyclic Quadrilateral

=> ∠QST = 180° - 65°

=> ∠QST =  115°

QSP is straight line

=> ∠PST = 180° - ∠QST

=> ∠PST = 180° - 115°

=> ∠PST = 65°

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