Question

in figure , PQRS is a rectangle with QPR=31° . find the value of ROS​

Answer 1

ROS=118...................

Answer 2

Hello..!!

Given:- angle QPR = 31°

To find :- Value of angle ROS

Solution:- In ∆OPQ,

angle OPQ + angle OQP + angleOPQ=180° -------(1)

{angle sum property of triangle}

Also, we know that the diagonals of a rectangle bisect each other.

=> OP = OQ

=> Angle OPQ = Angle OQP = 31°

{angle opposite to equal sides are equal}

Now, putting these values in equation(1),

we get:-

angle OPQ = 180° - 62° =118°

Again, angle OPQ = angle ROS = 118°

{Vertically opposite angles}

Hence, the answer is --->>>

$\boxed{\underline{\textsf{ angle ROS=118°}}}$

$<b>$

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