Question

in figure , prove AF=1÷3 AC using B.P.T​

Answer 1

Answer:

CONST- DRAW DM║BF

PROOF- IN ΔADM

GF║DM (DM║BF)

⇒AG/GD= AF/FM

⇒1=AF/FM  (AG=GD)

⇒AF=FM   (1)

NOW, IN ΔBCF

BF║DM

⇒BD/CD= FM/CM    (BPT)

⇒1=FM/CM  (BD=CD)

⇒FM=CM   (2)

FROM 1 AND 2, WE GET

FM=AF=CM (3)

ALSO, AF+FM+CM=AC

AFAF+AF=AC   (FROM 3)

3AF=AC

AF=1/3 AC

HENCE PROVED:)

Step-by-step explanation: