Question

in figure,PS=3 cm,QS=4 cm,angle PRQ =theta,angle PSQ=90 degree, PQ perpendicular to RQ and RQ =9 cm.Evaluate tan theta.

Answer 1

❤❤HERE IS YOUR ANSWER ❤❤

In triangle PSQ,

(PQ)^2=(PS)^2+(SQ)^2

(PQ)^2=(3)^2+(4)^2

(PQ)^2=9+16

(PQ)^2=25

(PQ) =5

tan theta =opp./adj.

[tan theta =5/9]

❤❤payal❤❤

Answer 2

Answer: -

Tan = 0.556