Question

IN FIGURE PS PERPENDICULAR L AND RQ PERPENDICULAR L FIND Y​

Answer 1

Answer:

80 is answer of this question

Step-by-step explanation:

you want step by step then tell me <srn+<srp=180 ( linear pair )

135+<srp=180

<srp=45

srp+prq=45+55

srq=100

the sum of all angle of a quadrilateral is 360

90+90+100+y=360

y=360-280

y=80

Answer 2

$\underline\mathfrak\red{Answer:}$

In ∆ PQR, we have

$\angle$PRQ + $\angle$PQR + $\angle$QPR = 180°

55°+90°+$\angle$QPR = 180°

145° + $\angle$QPR = 180°

$\angle$QPR = 180°-45°

$\angle$QPR = 35°

______________________

Since, PS $\perp$ l, therefore

$\angle$SPQ = 90°

$\angle$SPR +QPR = 90°

$\angle$SPR + 35° = 90°

$\angle$SPR =90°-35°

$\angle$SPR = 55°

______________________

In, ∆PSR, we have

Exterior $\angle$ = sum of two interior opposite angles

135°= y + $\angle$SPR

y = 135° - $\angle$SPR

y = 135° - 55°

y = 80°

Hence, the measure of y is 80°.