in figure ps perpendicular to i and rq perpendicular to i find y
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value of y= 135°
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abarajith876911:
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Let the angle SRP be x
So from linear pair property
x+135=180°
so x=180-135
=45°
So angle SRQ=100
In quadrilateral PSRQ,
y+100+90+90=360
y=360-280
So y=80°
Hope this helps.
So from linear pair property
x+135=180°
so x=180-135
=45°
So angle SRQ=100
In quadrilateral PSRQ,
y+100+90+90=360
y=360-280
So y=80°
Hope this helps.
hii
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