In figure, PS/SQ = PT/TR and ∠PST = ∠PRQ.
Prove that ΔPQR is isosceles triangle.
Solve with complete steps and reasoning.
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Answered by
13
Hi ,
It is given that ,
PS / SQ = PT /TR a and
<PST = <PRQ
RTP : ∆PQR is isoseceles.
Proof :
In ∆PQR
PS/SQ = PT/TR
Therefore ,
ST // QR [ By converse of Thales Theorem ]
Now ,
ST // QR , PQ is the transversal ,
<PST = <PQR ---( 1 )
[ corresponding angles ]
<PST = <PRQ ( given ) ----( 2 )
from ( 1 ) and ( 2 ) ,
<PQR = <PRQ ---( 3 )
In triangle PQR ,
<PQR = <PRQ
Therefore ,
PR = PQ
[ sides opposite to equal angles are equal ]
∆ PQR is isoseceles.
Hence proved.
I hope this helps you.
: )
It is given that ,
PS / SQ = PT /TR a and
<PST = <PRQ
RTP : ∆PQR is isoseceles.
Proof :
In ∆PQR
PS/SQ = PT/TR
Therefore ,
ST // QR [ By converse of Thales Theorem ]
Now ,
ST // QR , PQ is the transversal ,
<PST = <PQR ---( 1 )
[ corresponding angles ]
<PST = <PRQ ( given ) ----( 2 )
from ( 1 ) and ( 2 ) ,
<PQR = <PRQ ---( 3 )
In triangle PQR ,
<PQR = <PRQ
Therefore ,
PR = PQ
[ sides opposite to equal angles are equal ]
∆ PQR is isoseceles.
Hence proved.
I hope this helps you.
: )
GovindKrishnan:
Thanks Sir for the answer!
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9
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