Question

in figure QR = 12 , BC = 8 , PS = 6 , AD = 3 then A (PQR) , A( ABC ) =

please guys answer me then i will brainlist you​

Answer 1

Answer:

A(pqr) .... 1/2*12*6. =36

A(abc) ....1/2*8*3 =12

now 36/12=3/1

Answer 2

Answer:

The ratio of the areas of the given triangles is 3sq.units.

Step-by-step explanation:

Area of a triangle is the region enclosed by the three sides.

Area of a triangle is equal to half of the product of its base and height i.e.,

$A=\dfrac{1}{2}\times\mbox{base} \times \mbox{hieght}=\dfrac{1}{2}bh$

Given in a triangle PQR,

the base is QR and its length is, b = 12units

the height is PS, and the measure is, h = 6units

Thus, the area of triangle PQR is

$A\{\triangle PQR\}=\dfrac{1}{2}\times 12\times6=6\times6=36~\mbox{sq.units}$

Given in a triangle ABC,

the length of the base BC is, b = 8units

the height of the triangle AD is, h = 3units

Thus, the area of triangle ABC is

$A\{\triangle ABC\}=\dfrac{1}{2}\times 8\times3=4\times3=12~\mbox{sq.units}$

Therefore, the ratio of the areas of the triangles is

$\dfrac{A\{\triangle PQR\}}{A\{\triangle ABC\}} =\dfrac{36}{12}=3~\mbox{sq.units}$

Therefore, the ratio of the areas of the given triangles is 3sq.units.

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