Question

In figure QT parallel PR angle TQR=60° and angle SPR = 40°. find the values of x and y​

Answer 1

this is the answer!!!!!!

Answer 2

x = 30° and y = 70°

Given:

T perpendicular to PR

angle TQR=60°

angle SPR = 40°

To find:

find the values of x and y​

Solution:

∠ RTQ = 90°(T perpendicular to PR )

In Δ QTR,

∠QRT + ∠RTQ + ∠TQR = 180°( Sum of angles of a triangle)

x + 90° + 60° = 180°

x + 150° = 180°

x = 180°- 150°

x = 30°

In Δ PSR,

∠PSQ = ∠SPR + ∠PRS( exterior angle of triangle is sum of opposite interior angles)

y = 40°+ 30°

y = 70°

Hence, x = 30° and y = 70°.

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