In figure, seg RS is a diameter of the circle with
centre O. Point T lies in the exterior of the circle.
Prove that RTS is an acute angle.
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Answer :
angle RTS is an acute angle
Step by step explanation :
constuction:-
Draw seg RT and RS
Take point P on the circle on line RT
Draw seg PS
Proof :-
In triangle RPS,
angle RPS =90° -(1) (angle inscribed in semicircle is right angle)
In triangle PST,
angle RPS is an exterior angle of triangle PST
angle RPS > angle PTS (Exterior angle theorem)
i.e. angle PTS < angle RPS
angle PTS < 90° [from (1)]
angle RTS < 90° (R-P-T)
i.e. angle RTS is an acute angle
Hence Proved
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