Question

In figure shown below the coefficient of kinetic friction between 5kg and 3kg blocks is 0.4. The table on which blocks are placed is smooth.The acceleration of the system is​

Answer 1

Answer:

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Answer 2

Answer:

The acceleration or coefficient of the system can be found using the net force acting on the design and the total mass of the system of kinetic friction.

Explanation:

Since the coefficient of kinetic friction is given as 0.4, the force of friction acting on the system is 0.4 * normal force.

The normal force is equal to the weight of the blocks, which is the force of gravity acting on them. The weight of the 5kg block is (5 kg) * (9.8 m/s^2) = 49 N, and the weight of the 3kg block is (3 kg) * (9.8 m/s^2) = 29.4 N. So the normal force is 49 N + 29.4 N = 78.4 N.

The force of friction is then (0.4) * (78.4 N) = 31.36 N.

The net force acting on the system is the force of friction in the opposite direction to the direction of motion.

The acceleration of the system can be found using the second law of motion: F = ma, where F is the net force, m is the total mass of the system, and a is the acceleration.

As we know, F = -31.36 N and m = 5kg + 3kg = 8kg

so, a = F/m = -31.36 N / 8 kg = -3.92 m/s^2

Therefore, the acceleration of the system is -3.92 m/s^2 (in the opposite direction of motion due to the friction force).

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