in figure sides of angle pqr angle xyz are parallel to each other prove that angle pqr is congruent triangle xyz
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PQ || XY and PQ = XY
PR || XZ and PR = XZ
Taking Δ PQR and ΔXYZ
PQ = XY
PR = XZ
∠ QPX = ∠YXM = a
∠ RPX = ∠ZXM
∠XYZ = ∠YXM + ∠ZXM = a + b
∠XYZ = ∠QPR = a + b
ΔPQR ≅ ΔXYZ (SAS)
ar (ΔPQR) = ar. (Δ XYZ)
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