Question

In figure, the diameter AB of circle with centre 'O' is
perpendicular to the chord PQ If PQ=8cm and AM=2cm
find the radius of circle​

Answer 1

Answer:

Let the centre of the circle be O.

AB = 12 cm

OC = 12 cm

OC ⊥ AB

We know perpendicular drawn from the centre of the circle to the chord, bisects the chord.

So, AC = 6 cm

In ⃤ OCA,

OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10

Thus, AO = 10 cm

Diameter = 2 × 10 cm = 20 cm.

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