In figure, the sides AB, BC and CA of a triangle ABC touch a circle at P, Q and R respectively. If PA = 4 cm, BP = 3 cm and AC = 11 cm, find the length of BC (in cm).
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Answer:
The answer is 10 cm
Step-by-step explanation:
As given
PA=4cm
BP=3cm
∴AB=4+3=7cm
AC=11cm
As PA and RA is two tangents from same external point A
∴RA=PA=4cm
⇒RC=AC−RA
⇒RC=11−4=7cm
As RC and QC is two tangents from same external point C
∴QC=RC=7cm
As BP and BQ is two tangents from same external point B
∴BP=BQ=3cm
Then BC=QC+BQ
⇒BC=7+3=10cm
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