In figure TP | | SR and PQ = PR, find the value of ∠PQS.
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Answer:
<PQS = 130°
Step-by-step explanation:
<UPR = 50° (Vertically Opposite angles)
<UPR = <PRQ (Alternative Interior angles)
Since, PQ = PR
Therefore ∆PQR is an isosceles triangle
So, <PQR = <PRQ (Base angles are equal)
Thus, <PQR = 50°
<PQS + <PQR = 180° (Linear Pair)
<PQS + 50° = 180°
<PQS = 180° - 50°
<PQS = 130°
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