in figure TR prepindicular PS, PQ parallel TR, PS parallel QR . if QR=8cm , PQ=3cm and SP=12cm . find area PQRS
Hriday0102:
Can u plz give the pic of the figure
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ptrq is a parellelogram
area of parellogram= base* height=8*3=24 cm²
str is a right angled triangle
area of str=1/2*base*height
=1/2*ts*tr
ts=sp-pt
pt=qr=8 cm
ts=12-8=4cm
area of str=1/2*4*3=6cm²
area of pqrs=area of ptrq+area of str
=24+6=30 cm²
area of parellogram= base* height=8*3=24 cm²
str is a right angled triangle
area of str=1/2*base*height
=1/2*ts*tr
ts=sp-pt
pt=qr=8 cm
ts=12-8=4cm
area of str=1/2*4*3=6cm²
area of pqrs=area of ptrq+area of str
=24+6=30 cm²
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