In figure triangle ABC =AKH given that
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Two Triangles are said to be similar if their i)corresponding angles are equal and ii)corresponding sides are proportional.(the ratio between the lengths of corresponding sides are equal)
GIVEN:
AK = 10cm, BC = 3.5cm & HK = 7cm
∆AHK ~ ∆ABC
AK/AC = HK/BC
[corresponding sides of similar triangles are proportional]
10/AC = 7/3.5
10/AC = 70/35
10/AC = 10/5
10AC = 10 × 5
AC = (10 × 5) /10
AC = 5 cm
Hence, the value of AC is 5 cm.
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