in figure triangle ABC smiliar yo trianglePQR then y+z
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if the measures of the corresponding sides of two triangles are proportional then the triangles are similar.
PQ/AB = PR/AC = QR/BC
3/Z = Y/4√3 = 6/8
3/Z = 6/8
⇒ Z = 24
Y/4 √3 = 6/8
⇒Y = 3 √3
Therefore, Y+Z = 3 √3+24
PQ/AB = PR/AC = QR/BC
3/Z = Y/4√3 = 6/8
3/Z = 6/8
⇒ Z = 24
Y/4 √3 = 6/8
⇒Y = 3 √3
Therefore, Y+Z = 3 √3+24
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