IN FIGURE TWO ANGLES AB AND CD ARE INTERSECTING AT O AND ANGLE FORMED AT O ARE marked the value of angle x and angle y
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Since AB and CD intersect at O
⇒ ∠BOD = ∠AOC ⇒ a = 4b (i)Also a + b + 60° = 180° Þ a + b = 120° (ii) or 4b + b = 120° ⇒ 5b = 120° ⇒ b = 24° ⇒ a = 4b = 4 x 24 = 96°Since ∠AOD = ∠COB (Vertically opposite angles) ⇒ 2c = 60° + b ⇒ 2c = 60° + 24° = 84° c = 42°
Hence a = 96°, b = 24°, c = 42°
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