In figure ZAOC and ZBOC from a linear pair. If a-2b = 30° find a and b С a a a b KE O B.
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∠AOC and ∠BOC form a linear pair.
∠AOC=a and ∠BOC=b
∴ a+b=180
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[ Linear pair ] ------ ( 1 )
⇒ a−2b=30
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----- ( 2 )
Subtracting equation ( 2 ) from ( 1 ) we get,
⇒ 3b=150
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⇒ b=50
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Substituting value of b in ( 1 ) we get,
⇒ a+50
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=180
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∴ a=130
o
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