Question

In figure1.55, ∠ABC=75°,∠EDC=75° state which two triangles are similar and by which test? Also write the similarity of these two triangles by a proper one to one correspondence.

Answer 1

Answer:

Δ ABC  ~  Δ EDC

AC/EC  = BC/DC= AB/ED  

Step-by-step explanation:

in Δ ABC

∠ABC = 75 °

∠BCA = x °

∠BAC = 180° - 75° - x° = 105 - x°

in Δ EDC

∠EDC = 75 °

∠ECD = x °

∠CED = 180° - 75° - x° = 105 - x°

∠ABC = ∠EDC

∠BCA = ∠ECD

∠BAC = ∠CED

All the angles are same hence

Δ ABC  ~  Δ EDC   ( AAA Similarity )

AC/EC  = BC/DC= AB/ED  

Answer 2

Answer:

hope it is help ful

Step-by-step explanation:

if it is correct then mark as brainlist